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The probability of finding 2s electron will be : `Psi_(2s)^(2) = (1)/(32pi) ((1)/(a_(0)))^(3) (2- (r_(0))/(a_(0)))^(2) e^(-2r//a_(0))` <br> Node is the point at which probability of finding electron is zero. Thus, `Psi_(2s)^(2) = 0` when `r = r_(0)` <br> `:. (1)/(32pi) ((1)/(a_(0)))^(2) (2 - (r_(0))/(a_(0)))^(2) e^(-2r_(0)//a_(0)) = 0` <br> In this expression, the only factor that can be zero is `(2 - (r_(0))/(a_(0)))` <br> Thus, `2 - (r_(0))/(a_(0)) = 0 or r_(0) = 2 a_(0)`